2x+5=6x^2

Solution for 2x+5=6x^2 equation:

2x+5=6x^2

We move all terms to the left:

2x+5-(6x^2)=0

determiningTheFunctionDomain
-6x^2+2x+5=0

a = -6; b = 2; c = +5;
Δ = b2-4ac
Δ = 22-4·(-6)·5
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{31}}{2*-6}=\frac{-2-2\sqrt{31}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{31}}{2*-6}=\frac{-2+2\sqrt{31}}{-12}
$